In c$++$ please $.$ Write a program that converts values using decimal and binary prefixes. Historically, computer

professionals have used the SI prefixes kilo, mega, giga, etc. to mean multiples of $2^{10}$ instead of the usual

${10}^3$ : a kilobyte $(KB)$ is $1024$ bytes, a megabyte $(MB)$ is $(10241024)$ bytes, etc. This was convenient since

computer professionals generally work in powers of two, and $1024$ is "close enough" to $1000.$ In

computing, the meaning of $KB,MB,$ etc. is not always based on multiples of $2^{10}.$ Disk and solid$-$state drive

manufacturers assume that a KB is $1000$ bytes, a MB is $(10001000)$ bytes, and so forth. Therefore,

today's drive capacities are measured in GB $({10}^9$ bytes$)$ or TB $({10}^{12}$ bytes$).$ Computer hardware engineers

and software developers still generally refer to powers of two when sizing memory. As the values

represented by the prefixes get larger, so does the divergence between the binary and decimal

meanings of the prefixes. The prefixes are as follows:

By using the binary prefixes from above and reserving K$,$ M$,$ G$,$ etc. for decimal multiples, it is possible

to clearly state what is intended when discussing storage or network needs.

Input from the keyboard value requests in bytes. The line of input will contain three values

separated from each other by single spaces: a positive numeric value which may include a decimal point,

the unit for that value, and the desired unit that the value is to be expressed in$.$ The units will be one of

$[$KB$,$ MB$,$ GB$,$ TB$,$ KiB, MiB, GiB, TiB$].$ Assume all conversion requests will be less than $250$ bytes.

Output to the screen the result on a separate line. Round the result to three decimal places after the

decimal point and print without leading zeroes or spaces. This result is followed by a single space and

the abbreviation for the desired unit without trailing whitespace. Finally, the program should ask if the

user wants to run the program again $($Check case$).$ Refer to the sample output below.

Sample Run:

Enter values: $4$ TB MiB

Result: $3814697\mathrm{.}266$ MiB

Run Again $(\frac{Y}{N}$ : y

Enter values: $0\mathrm{.}5$ GB MiB

Result: $476\mathrm{.}837$ MiB

Run Again $(\frac{Y}{N})$: N