Question: In C Programming please. Write a function named toRemainder (..) which takes an array arr and a number k as input argument. Upon calling the

In C Programming please.

In C Programming please. Write a function named toRemainder (..) which takes

Write a function named toRemainder (..) which takes an array arr and a number k as input argument. Upon calling the function, each element in the array should be replaced by the remainder of the element divided by the number k. The input array should be passed to the function using a pointer and all the computation should be done using pointer arithmetic. How do you access the size of the array inside the toRemainder (..)? Remainder: If we want to divide an integer A by another integer B, then the remainder is the integer left over after dividing A by B to produce another integer called quotient (the division result). Example: 15 divided by 4 gives 3 as quotient and 3 as remainder 15 divided by 5 gives 3 as quotient and 0 as remainder 17 divided by 5 gives 3 as quotient and 2 as remainder etc. ** In C, you can achieve remainder by using modulo (%) operator. For example the expression 17%5 evaluates to 2 and expression 15%5 evaluates to 0, likewise. Example cases: Input array: arr = [4, 3, 4, 12, 5, 16), k=5 Print in the main after calling the toRemainder(..) with arr and k as argument, Expected output: [4, 3, 4, 2, 0, 1)

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