Question: In class we found a private key d for the following RSA values: P = 7, and q = 13. We computed N = 91

In class we found a private key d for the following RSA values: P = 7, and q = 13. We computed N = 91 and = 72. Then for e = 41 we computed d = e-1 mod 72. Simplify this problem and instead of = (p-1) (q-1) take = LCM( (p-1), (q-1)) and compute d modulo this . Now use this new private key to decrypt our ciphertext 48. Show your work.

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