Question: In double slit diffraction where d = 0 . 2 5 mm , the phase angle is = 4 . What is the path difference

In double slit diffraction where d =0.25 mm, the phase angle is =4. What is the path difference if the wavelength of light passing through the slits is 600 nm? What fraction of the maximum intensity will the intensity be for this phase difference. You are solving for I Io . What is the viewing angle when =4.

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