In $($Figure $1),$ coordinate direction angles for F$3=500$ lb are $\backslash$alpha $=140,\backslash$beta $=50,$ and $\backslash$gamma $=75$

Part A

Determine the magnitude of the resultant force acting on the eyebolt.

Express your answer in pounds to three significant figures.

Fr$=?$

Part B

Determine coordinate direction angle $\backslash$alpha of the resultant force.

Express your answer in degrees to three significant figures.

$\backslash$alpha $=?$

Part C

Determine coordinate direction angle $\backslash$beta of the resultant force. Express your answer in degrees to three significant figures.

$\backslash$beta $=?$

Part D

Determine coordinate direction angle $\backslash$gamma of the resultant force. Express your answer in degrees to three significant figures.

$\backslash$gamma $=?$