In (Figure 1) , let C1 = 3.50 F , C2 = 5.00 F , and Vab

In (Figure 1) , let C1 = 3.50 μF , C2 = 5.00 μF , and Vab = +68.0 V.

 

Part A

Calculate the charge on capacitor C1.

Part B

Calculate the charge on capacitor C2

Part C

Calculate the potential difference across capacitor C1

Part D

Calculate the potential difference across capacitor C2

Transcribed Image Text:

+Q CVac = V1 Vab = V C, Veb = V, b + +Q CVac = V1 Vab = V C, Veb = V, b +

Answer rating: 100% (QA)

Here C1 and C2 are in series Hence Net capacitance is Cnet C1C2C1C2 35... View the full answer