Question: IN JAVA 3.23 LAB: Leap year A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate

IN JAVA 3.23 LAB: Leap year A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400; therefore, both 1700 and 1800 are not leap years Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is: 1712 the output is: 1712 - leap year Ex: If the input is: 1913 the output is: 1913 - not a leap year

#include int main() { int year; bool isLeapYear=false; //Accept the user input scanf("%d",&year); //First check if the number is divisible by 400 //(which should also be divisible by 4 and 100) if(year%400==0) isLeapYear=true;

//Check if it is divisible by 100, if so then it is not leap else if(year%100 == 0) isLeapYear=false;

//check if it is divisible by 4 else if(year % 4==0) isLeapYear=true;

//Finally, if is not divisible, then not a leap year else isLeapYear=false;

//print results if(isLeapYear==true) printf("%d - leap year",year); else printf("%d - not a leap year",year);

return 0; }

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