In lab you created the T88ble, now you will create arr88, which are similar to numpy arrays from Data 8. Complete thelen and item functions according to the docstrings. len is a special attribute, like_init that allows us to call len on our Arr88s to get their length! def en (self): add and muare also special attributes, likeinit and enthat allow us to use + and on our Arr88s to add/mult ply them componentw se! Question 1 Get the length of the Arr88 arr88 Arr88([1, 2, 3]) >len(arr88) 2defadd_ (self, arr88): Add two ArrB8s of the same length componentwise arr88Arr88([1, 2, 3, 41) len(arr88) arr88aArr88([1, 2, 31) arr88bArr88( [4, 5, 61) arr88aarr88b Arr88( [5, 7, 91) >>> arr88a # We aren't mutating arr88a Arr88([1, 2, 31) YOUR CODE HERE return def item(self, i): arr88aarr88b Arr88(['Hello', 'World,'') Get the item of the Arr88 at index i arr88ArrB8( [1, 2, 31) arr88.item(1) # Checks that the lengths are the same assert len(self) :-len (arr88) YOUR CODE HERE arr8B. item(0) return def-mul-(self, arr88): YOUR CODE HERE return Multiply two Arr88s of the same length componentwise arr88aArr88(11, 2, 31) arr88bArr88([4, 5, 6]) arr88a arr88b Arr88(14, 10, 18]) >>> arr88a # We aren't mutating arr88a Arr88([1, 2, 31) arr88bArr88( [18, 1, 51) arr88aarr88b Arr88(['NaNaNaNaNaNaNaNaNaNa",'Batman''!!!' # Checks that the lengths are the same assert len(self len(arr8B YOUR CODE HERE return Complete the apply function that returns a new Iist with the function applied to every element. def negate(self: def apply(self, func): Negate an Arr8B with mutation arr88aArrBB([1, 2, 3]) 3Apply a function to an Arr88 >>> arr88b = Arr88( [4.0,-5.5, 8.0)) >>> arr88a=Arr88([1, 2, 31) arr88a.negate() arr88a arr88a.apply(lambda x x *x) Arr88[1, 4, 91) >>> arr88a # We aren't mutating arr88a Arr88( [1, 2, 31) Arr88(-1, 2,-31) arr88b.negate) arr88b arr88bArr88(lambda x: x, Lambda x: x arr88b.apply(lambda f: f(1)) 1, lambda x: x 2]) ArrB8(I-4.8, 5.5, 0.0) Arr88([1, 2, 31) YOUR CODE HERE return YOUR CODE HERE return