In mathematics, theres a series called Arithmetic Series. Basically, you add a number of the previous term to obtain the next term. But if you have the difference d between two terms and the value a1of first term in the series, you can very easily calculate the nth term.

The formula for nth term an is given by: an = a1 + (n-1)d

Write an assembly program in the 'assembly x86-64 language' to calculate the nth term from the given data in variables [a1] and [d] in data section and store the calculated nth value in rax. But if the value in [d] is zero or less than zero, just set rax to zero.

Below is a template you can use to write your code

; template program

EXIT_SUCCESS equ 0

SYS_exit equ 60

a1 dd 7 ; the 1st term of the series

d dd 2 ; the difference between two terms

section .text

global _start

_start:

mov rcx, dword [var1] ;

_bye:

mov rax, SYS_exit

mov rdi, EXIT_SUCCESS

syscall