In networking, the bandwidth-delay product (BDP) metric is obtained by multiplying a link's bandwidth by the round-trip time (RTT). Assume a home is connected to an Internet Service Provider's (ISP) access point with a 3 km optical fiber at 70 Mbps. The speed of signal in an optical fiber is approximately 70% of the speed of light, the latter itself being approximately 300,000 km/s. The ISP uses a sliding-window protocol (see Lecture 1.) 

a) Calculate the BDP over this optical fiber.

b) What should be the minimum window size in order to get 100% efficiency; i.e., no sender idle time?

c) How does this minimum window size compare to BDP? Based on this, what is the physical meaning of BDP?

d) Assume the ISP moves the access point for this home further away. As a result, the optical fiber length becomes 3.75 km. What will be the efficiency if we still use the same window size as before? To reach 100% efficiency again, what should be the new window size?

e) In all of the above, does the size of the packet have any impact on efficiency? Explain.

Answer rating: 100% (QA)

a To calculate the BandwidthDelay Product BDP we multiply the links bandwidth by the roundtrip time RTT Given Link bandwidth B 70 Mbps megabits per se... View the full answer