In the code below, the first printf statement prints out A[3][5] = 35 What does the...

Transcribed Image Text:

In the code below, the first printf statement prints out "A[3][5] = 35" What does the second printf statement print out? int main(int argc, char *argv[]) { } int i, j; int A[8][6]; for(i = 0; i <8; i++) for(j = 0; j<6; j++) A[i][j] = i * 10+ j; printf("A[3][5] = %d\n", A[3][5]); int *p = &A[2][3]; printf("p[7] = %d\n", p[7]); 13 In the code below, the first printf statement prints out "A[3][5] = 35" What does the second printf statement print out? int main(int argc, char *argv[]) { } int i, j; int A[8][6]; for(i = 0; i <8; i++) for(j = 0; j<6; j++) A[i][j] = i * 10+ j; printf("A[3][5] = %d\n", A[3][5]); int *p = &A[2][3]; printf("p[7] = %d\n", p[7]); 13

Answer rating: 100% (QA)

In the given code the first printf statement prints out A35 35 because the value at index 35 of ... View the full answer