In the example shown above, why do we see the notation "f (a) . f (@ )" as part of Step 1? of(x) . f(x)= u . v. In our problem, u = f (x), and du = f' (x) da, so v = f (x). O This is the antiderivative of the given integrand, f(x) . f(x)=ff(x) . f (x) da. of(x) . f(x)=udu. In our problem, u = f (x), and du = f' (x) da. So v = f (x) and du = f' (x)