In the most common isotope of Hydrogen the nucleus is made out of a single proton. When this Hydrogen atom is neutral, a single electron orbits around the nucleus. What is the ratio of the electric force and the gravitational force acting between the proton and the electron, when they are $5\mathrm{.}05$ angstrom away from each other? $($Possibly useful constants: Coulomb constant: k $=8\mathrm{.}9876$times $109$ N$*$m$2/$C$2,$ Universal Gravitational constant: G $=6\mathrm{.}6726$times $10-11$ N$*$m$2/$kg$2,$ elementary charge: e $=1\mathrm{.}6022$times $10-19$ C$,$ electron mass: me $=9\mathrm{.}1094$times $10-31$ kg$,$ proton mass: mp $=1\mathrm{.}6726$times $10-27$ kg$.$ You might also find the specific charges i$.$e$.$ charge per mass ratios of the electron and the proton useful: electron: e$/$me $=1\mathrm{.}7588$times $1011$ C$/$kg; proton: e$/$mp $=9\mathrm{.}5788$times $107$ C$/$kg$.)$

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