In the structure shown, $10-$mm$-$diameter pins are used at $\backslash ($ A$,$ B $\backslash )$ and $\backslash ($ D $\backslash ).$ Knowing that the ultimate shearing stress is $100$ MPa and the ultimate bearing stress is $300$ MPa at all connections and that the ultimate normal stress is $250$ MPa in each of the two links joining $\backslash ($ B $\backslash )$ and $\backslash ($ D $\backslash ),$ determine the allowable load $\backslash (\backslash$mathbf$\{$P$\}\backslash )$ if an overall factor of safety of $2\mathrm{.}5$ is desired.