In this problem we revisit the problem from Lab 3.3 on the

student career conference. The

system included the following equations

:

R

x

=

5

represents revenue and

C

x

=

+

300

2 50

.

represents cost. In each case

x

represents the number of student participan

ts. The revenue

(

R )

is earned from registration fees. The costs (

C)

are from printing the promotional flyer

and ordering lunches for

x

students.

In business, the point of intersection of a cost graph and a revenue graph is calle

d the

break

-

even point

. The profit (

P

) is the difference of revenue (

R

)

and cost (

C)

. If the profit is

positive, the conference made money. If the profit is negative, the conference lost money.

The break

-even point is where the profit is zero; i.e. reve

nue equals cost.

a)

Algebraically determine the number of student participants that will make the conference

break-

even. That is, when revenue = cost.

b)

How many student participants are needed in order for the conference to have a profit?

Write t

his as an inequality: either

x

>

or

x

<

.