#include

$//$ Function to find square root of given number up to given precision

float squareRoot$($int number, int precision$)\{$

int start $=0,$ end $=$ number;

int mid;

$//$ variable to store the answer

float ans;

$//$ for computing integral part of square root of number

while $($start $<=$ end$)\{$

mid $=($start $+$ end$)/2$;

if $($mid $*$ mid $==$ number$)\{$

ans $=$ mid;

break;

$\}$

$//$ incrementing start if integral part lies on right side of the mid

if $($mid $*$ mid $<$ number$)\{$

start $=$ mid $+1$;

ans $=$ mid;

$\}$

$//$ decrementing end if integral part lies on the left side of the mid

else $\{$

end $=$ mid $-1$;

$\}$

$\}$

$//$ For computing the fractional part of square root up to given precision

float increment $=0\mathrm{.}1$;

for $($int i $=0$; i $<$ precision; i$++)\{$

while $($ans $*$ ans $<=$ number$)\{$

ans $+=$ increment;

$\}$

$//$ loop terminates when ans $*$ ans $>$ number

ans $=$ ans $-$ increment;

increment $=$ increment $/10$;

$\}$

return ans;

$\}$

$//$ Driver code

int main$()\{$

$//$ Function calling

printf$("\%.*$f

$",3,$ squareRoot$(50,3))$;

$//$ Function calling

printf$("\%.*$f

$",4,$ squareRoot$(10,4))$;

return $0$;

$\}$

please explain this C code and also manual trace it