#include #include

using namespace std;

void readNum (int N[],int& length) { string num;

cout

for (int i=20; i>=0; i--) { N[i]=num%10;

num=num/10;

}

length= strlength(N) }

int sumNum (int N1[], int numOfDigitsN1, int N2[], int numOfDigitsN2) { int size = numOfDigitsN1 + numOfDigitsN2;

int sum[size];

for (int i=size ; i>=0; i--) { sum[i]=N1[i] + N2[i];

if (sum[i] >=10) { N1[i+1]=N1[i+1]+1; sum[i]=(N1[i]+N2[i])&10; }

}

return sum[size]; }

int main () { int n1[20],n2[20],l1,l2;

readNum(n1,l1);

readNum(n2,l2);

cout

return 0; }

Exercise 3: Adding Large Integers In C++, the largest integer value is 2147483647. So, an integer larger than this number cannot be stored and processed as an integer. Similarly, if the sum or product of two positive integers is greater than 2147483647, the result will be incorrect. One way to store and manipulate large integers is to store each number as an array (each individual digit of the number will be stored as one element in the array). Write a program that reads two positive integers of, at most, 20 digits, and outputs the sum of the numbers. If the sum of the numbers has more than 20 digits, output the sum with an appropriate message. The program should use the follwing two functions