#include  int circular_right_shift(int a[], int output[], int n, int k) { // WRITE YOUR CODE HERE } // DO NOT MODIFY THE CODE BELOW int print_output(int output[], int n) { int i = 0; for (i = 0; i < n; i++) { printf("%d ", output[i]); } printf(" "); return 0; } int main() { int a[10240]; int output[10240]; int n, k, i; // read the input array and k scanf("%d", &n); scanf("%d", &k); for (i = 0; i < n; i++) { scanf("%d", &a[i]); } // initialize the array output for (i = 0; i < n; i++) { output[i] = 0; } int res = circular_right_shift(a, output, n, k); print_output(output, n); return 0; } -----------------------------------------End of Code----------------------------------------- Input: The first line contains two integers: N and k (k can be 0); The second line contains a, an array of N integers, a_0, a_1, ..., a_(N-1); 0 <= N <= 10^3 Output: The shifted array. Sample Input 1: 4 3 1 2 3 4 The first shift: 4 1 2 3 The second shift: 3 4 1 2 The third shift: 2 3 4 1 Therefore, Sample Output 1: 2 3 4 1 Sample Input 2: 1 5 100 Sample Output 2: 100 Sample Input 3: 3 0 3 2 1 Sample Output 3: 3 2 1