#include using namespace std;

int sum; const int num_threads = 4;

void foo(int val) { for(int i = 0; i < 5; i++) {

sum = sum + val; }

}

void bar_1() { thread t[num_threads]; for (int i = 0; i < num_threads; i++) {

t[i] = thread(foo, i + 1);

t[i].join(); }

cout << "Sum is " << sum << endl; }

void bar_2() { thread t[num_threads]; for (int i = 0; i < num_threads; i++) {

t[i] = thread(foo, i + 1); }

cout << "Sum is " << sum << endl; for (int i = 0; i < num_threads; i++) {

t[i].join(); }

}

void bar_3() { thread t[num_threads];

for (int i = 0; i < num_threads; i++) {

t[i] = thread(foo, i + 1); }

for (int i = 0; i < num_threads; i++) {

t[i].join(); }

cout << "Sum is " << sum << endl; }

int main() { sum = 0; bar_1(); 

 sum = 0; bar_2(); 

sum = 0;

bar_3(); }

a) The code on the left outputs three values for sum (via the cout statements in the bar_1, bar_2, and bar_3 functions). sum is a global variable and see that its value is set to 0 before each call of bar functions.

What is the maximum possible value one can see on the screen? (Hint: The maximum is the same for all outputs).

_____________

b) (10 pts) What is the minimum possible value for each output? (Hint: The minimum values are different for different bar function calls).

bar_1: Sum is (Min) ________ bar_2: Sum is (Min) ________ bar_3: Sum is (Min) ________