Question: For the reaction: A + 2B P + Q in aqueous solution, the rate equation is d[P]/dt = k[A] [B] where k = 3.678
For the reaction: A + 2B P + Q in aqueous solution, the rate equation is d[P]/dt = k[A] [B] where k = 3.678 x 10-3 (mol L-1)-1 sec-1. At the start of the reaction 0.255 mole of A and 0.605 mole of B are dissolved in water and then mixed giving a total volume of 1.70 dm. Calculate the initial values of: (a) d[A]/dt (b) d[B]/dt (c) d[P]/dt (d) dng/dt (ng is the number of moles of B) (-1.96 x 104 mol L- sec-) (-3.93 x 104 mol L- sec-) (1.96 x 104 mol L- sec-) (-6.7 x 104 mol sec-)
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Answer A 2B P Q satrequation d P K df t 3678 x 103 Total Volum... View full answer
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