Question: The given Jupiter distance is 40/6 = 6.7 times that to Mars, which makes the required transmitter powers 6.7 = 45 times as much
The given Jupiter distance is 40/6 = 6.7 times that to Mars, which makes the required transmitter powers 6.7 = 45 times as much or the required receiver powers 1/45 as much Neither appears feasible. But a practical solution would be to reduce the bandwidth for the Jupiter link by a factor of about 50, making B = (5/50) x 10= 100 kHz.
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