Initial Value Problems In this module we will approximate the solutions of Initial Value Problems (IVPs). But before you begin, let's warm up by finding the exact solution of a directly integrable IVP. Exercise 1 Consider the IVP: = 5t - 10, y(O) = 1 Integrate the ODE to obtain the general solution for yo) and by substituting for the initial value solve for the exact solution. Select the correct answer from the following list. O 1012 - 101 O y(t) = 5t Oy) = 7 10 Nunu Oy(t) = 12 - 10t +1 Finding the exact solution for this problem wasn't too hard, but it becomes more complicated when the right hand side of the ODE depends on both y and 1 and sometimes we might not be able to find an exact solution so we look for a numerical approximation instead