Question: Instructions: Show your work for each question. Follow the Problem Solving Techniques to neatly answer the entire question (i.e., make sure you label your


Instructions: Show your work for each question. Follow the Problem Solving Techniques to neatly answer the entire question (i.e., make sure you label your coordinate axis frame). Use SI Units unless otherwise indicated. Each question is worth 20 points. 11. A 2kg block slides along a floor of negligible friction with a speed of 20 m/s when it collides with a 3kg block, which is initially at rest. |oa|=20 m S m |0b|= 0 0- S Mk = 0.0 Also, the graph below represents the force exerted on the 3kg block by the 2kg block as a function of time. Force (Newtons) 800- 600- 400- 200- -0 Force vs. time 0.050 0.070 0.090 0.110 time (seconds) (0.0531, 718.2) 11a. What is the initial momentum (vector!!) of the 2kg block? to = 0.05s t = 0.10s |Favg| = 400N 11b. What is the impulse (vector!) exerted on the 3kg block? 11c. Using the Impulse-momentum theorem, what is the final momentum (vector!) of the 2kg block immediately after the collision? uniformly, the anguler 7 at the init 11d. What type of collision is this? (HINT: It's not an explosion...) 0.097
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