Instructions:

Sketch a section detail using relative scale a section through a typical single family home foundation wall and first

floor framing, using all the following specified materials. You may choose to use the imperial $($inches$)$ or metric

$($millimeters$)$ dimensions based on your own preference. Place the exterior of the wall on the left side of the

detail. All the following elements must be shown and labeled $($where appropriate to do so$)$ in your sketch.

Footing and Foundation Elements

$18$

shown in Figure $31,$ page $67$ CHMC$).$

$4"(101)$ diameter perforated plastic drain tile beside outside face of footing. Cover the tile with $6"(152)$

of gravel, measured from the top of the tile. Draw the stones about $3/4"(19)$ in diameter

$8^{\text{'}\text{'}}(203)$ thick by $8^{\text{'}}-0^{\text{'}\text{'}}(2440)$ high concrete foundation wall, centered on the footing. Use break lines to fit

the detail on the sheet.

Wall reinforcing shall be $2-10M$ top and bottom full length, $2-15M$ vertical each side of all openings,

with $2-15M$ above and below those openings.

Window openings shall be formed by casting the PVC window into the wall, or by forming a buck using

$28$ pressure treated lumber.

$24$ pressure treated ladder frame cast into the top of the foundation wall.

Two coats of bituminous damp proof coating applied to exterior of wall and footing.

$\frac{1}{2}"(12\mathrm{.}7)$ cement parging, from the top of the concrete foundation wall to $8"$ below grade.

Exterior finished grade is $8"(203)$ below the top of foundation wall. Show this dimension.

Basement Floor Elements

$4^{\text{'}\text{'}}(101)$ thick concrete floor slab, resting on top of the footing.

$1/2"(12\mathrm{.}7)$ asphalt impregnated fiberboard joint filler between foundation wall and concrete floor slab.

$6$ mil polyethylene sheet moisture barrier under concrete slab.

$8(203)$ compacted granular fill $($sand and gravel$)$ under concrete.

Main Floor Elements

$5/8"(16)$ T&G $($tongue and groove$)$ plywood subfloor.

$\frac{91}{2}"$ engineered wood $"$ joists @ $16"(400)$ O$.$C$.$

$\frac{91}{2^{\text{'}\text{'}}}1\frac{1}{2\text{'}}$ rim board.