Question: } int main(int argc, char **argv) { char *buffer; unsigned short buffersize, i, index, length; if (argc < 2) usage(argv[0]); length = atoi(argv[1]); if (length
}
int main(int argc, char **argv) { char *buffer; unsigned short buffersize, i, index, length;
if (argc < 2) usage(argv[0]); length = atoi(argv[1]); if (length <= 0) { fprintf(stderr, "bad length "); return 1; } buffersize = length + 1; buffer = alloca(buffersize); memset(buffer, ' ', buffersize); buffer[buffersize - 1] = 0;
for (i = 2; i < argc; i++) { if (strlen(argv[i]) < 2) { fprintf(stderr, "bad command \"%s\" ", argv[i]); return 1; }
index = atoi(argv[i] + 1); if (index >= length) { fprintf(stderr, "bad index in command \"%s\" ", argv[i]); return 1; }
buffer[index] = argv[i][0]; }
Can someone please me solve this hacking challenge, I need to create a string in able to exploit the vulnerability.
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