Question: @. Integral legla # 1 8 / m: ( BX + 2 x 3 6x 2 ) dx /3 xdx + / 2 x 2x

 @. Integral legla # 1 8 / m: ( BX +
2 x 3 6x 2 ) dx /3 xdx + / 2

@. Integral legla # 1 8 / m: ( BX + 2 x 3 6x 2 ) dx /3 xdx + / 2 x 2x - / 6x dx = 3) xox + 2/ x 26x-6/x"dx - te+ 2 X 3+ 1 2 41 3 +1 et/ citcathy = Gy 3 X + 8 X 4 2 O X 2. te = 3X text - 2X+0 3 2 2 2 5 * + 6 * - 3 /x / dx

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