Question: Inter arrival time for new tech = a = 5 months. CVa = 1 Activity Time = p = 1 2 Months. CVp = 2

Inter arrival time for new tech= a =5 months. CVa=1 Activity Time =p =12 Months. CVp=2 Number of servers =3 Tq=33.25 months how do you get tq=33.25

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Inter arrival time for new tech = a = 5 months. CVa = 1 Activity Time = p = 1 2 Months. CVp = 2 Number of servers = 3 Tq = 3 3 . 2 5 months

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