Question: Is it correct 10. If a and b are constants such that x2 + ax = (x-b)(x+3) +6, find the values of a and b.

Is it correct

10. If a and b are constants such that x2 + ax = (x-b)(x+3) +6, find the values of a and b. x tax = (x-b)(x+ 3)+b L. HS. = tax R.H- S. = (x-b) (oct 3)+6 = x(xc+ 3)-6(xx+ 3)+6 - sez+3x-box- 36+6 - + (3- 6) x - 36+6 a = 3-b - 36+6=0 . a = / and 6- 2. -36=-6 3b= 6 b = 2

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