is this answer right? Using excel

4. (10 points) A production machine costs $4000 and has a 7-year useful life. At the end of 7 years, it can be sold for $10000. If interest is 10% compounded quarterly, what is the equivalent annual cost of ownership of this machine over its useful life? ia = (1+r/ mm - 1 ia = (1 +.1/4)^4 - 1 ia = .1038 -4000(A/P,10.38%,7) + 10000(A/F,10.38%,7) = -40000.207982) + 100000.104182) = -831.93 + 1041.82 = -209.90 (gain of 209.90)