is this correct for part b: To find the optimal solution, we need to evaluate the objective function at the extreme points of the feasible region. The objective function is: Maximize 50x1 + 20x2 + 25x3 Evaluating the objective function at the extreme points: (0, 0, 0) Objective function value = 50(0) + 20(0) + 25(0) = 0 (0, 87.5, 0) Objective function value = 50(0) + 20(87.5) + 25(0) = 1750 (55.56, 0, 0) Objective function value = 50(55.56) + 20(0) + 25(0) = 2778 (0, 0, 75) Objective function value = 50(0) + 20(0) + 25(75) = 1875 The extreme point with the highest objective function value is (55.56, 0, 0), which has a maximum profit of $2,778. Therefore, the optimal solution is to produce 55.56 units of product 1, 0 units of product 2, and 0 units of product 3, which will result in a maximum profit of $2,778