i.Show that 0.1011001₂ represents 0.6953125₁₀.

ii.Suppose that only 3 bits are available to store the fractional part of 0.1011001₂. The extra digits can either be cut off (truncated) to give 0.101, or rounded up to the next highest value, to give 0.110. Find the decimal equivalents of each of these fractional values (the truncated value and the rounded up value) and write each as a percentage of the actual value given in question b(i), rounded to the nearest tenth of a percent.

iii.State whether the truncated value or the rounded-up value is a better approximation of the actual value of 0.6953125₁₀.