It is decided to extract - A from a feed containing 20 mol% A and 80 mol% B in two ideal cross current stages as shown below, using equal amount of pure solvent C in each stage. Solvent Solvent Feed Raffinate 1 Raffinate 2 Stage 1 Stage 2 Extract 1 Extract 2 Components B and C are immiscible. 60% of A in the feed is extracted in Stage 1. The equilibrium relation is given by y* = 1.5x, where x is moles of A per mole of B in raffinate, y* is moles of A per moles of C in extract in equilibrium with raffinate. The mol% of A in raffinate from Stage 2 is (rounded off to second decimal place)