I've attempted to solve this problem and wanted to make sure I was right, I got 66.87%. Please advise and show detail step by step if possible if I missed something. Thank you!

Use the normal distribution of IQ scores, which has a mean of 100 and a I6 standard deviation of 11, and the following table with the standard scores and percentiles for a normal distribution to find the indicated quantity. g Click the icon to view the table. The percentage of scores between 94.5 and 122 is 66.87 %. (Round to two decimal places as needed.) Data table Standard Scores and Percentiles for a Normal Distribution (cumulative values from the left) Full data set I: Standard score \"In Standard % score - 3.0 0.13 0.1 53.98 - 2.5 0.62 0.5 69.15 - 2 2.28 0.9 81.59 - 1.5 6.68 1 84.13 -1 15.87 1.5 93.32 - 0.9 18.41 2 97.72 - 0.5 30.85 2.5 99.38 - 0.1 46.02 3 99.87 0 50.00 3.5 99.98