I(x, y) = [ (2t + 1) esint dt + x Consider the function defined by...

 

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I(x, y) = [ (2t + 1) esint dt + x Consider the function defined by - ( f(x, y) = xy(x²-y² x² + y² + 1² (2² 0 (2t - 1) tan (t²) dt (x, y) = (0,0) (x, y) = (0,0) (a) (8pt) Find f(x, y) and fy(x, y) for (x, y) = (0,0). (b) (2pt) Use the limit definition of partial derivatives to find f(0, 0) and fy(0,0). (c) (6pt) Use the limit definition of partial derivative to find fry (0,0) and fyr (0,0). I(x, y) = [ (2t + 1) esint dt + x Consider the function defined by - ( f(x, y) = xy(x²-y² x² + y² + 1² (2² 0 (2t - 1) tan (t²) dt (x, y) = (0,0) (x, y) = (0,0) (a) (8pt) Find f(x, y) and fy(x, y) for (x, y) = (0,0). (b) (2pt) Use the limit definition of partial derivatives to find f(0, 0) and fy(0,0). (c) (6pt) Use the limit definition of partial derivative to find fry (0,0) and fyr (0,0).

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a To find fxx y and fyx y for x y 0 0 we need to compute the partial derivatives of the function fx ... View the full answer