java

Consider the code: interface Quiszable ! public int doSomething (int a, int b, int c): 1 class QuizQuestion public static void printResult (Quizzable x) ! System.out.println(.doSomething (1,2,3)): 1 public static void main(String[] args) printResult( (xy ) -> x + y 2): 1 We pointed out that the lambda expression was equivalent (so much so, that the compiler rewrote the lambda) to another way to pass functionality (code) to the printResult() method. In the space below, write an additional class and a new main() method for QuizQuestion that allows for an unchanged printResult() method to still produce the same answer from the same computation, but does not use lambdas