java eclipse

/** * posOfSmallestElementGtOeT returns the position of the smallest element in the array that * is greater than or equal to the limit parameter * if all values are smaller than theVal, return -1; * * Precondition: the array is nonempty and all elements are unique. * Your solution may go through the array exactly once. * * * * *

 0 == posOfSmallestElementGtOeT(3, new double[] { 7 }) 3 == posOfSmallestElementGtoeT(3, new double[] { 11, -4, -7, 4, 8, 1 }) -1 == posOfSmallestElementGtOeT(17, new double[] { 1, -4, -5, 7, 8, 11 }), // value: 7 is in poso // value: 4 is in pos 3 // all elements are  public static int posOfSmallestElementGtOeT( double limit, double[] list) { * * * stringReformat takes a person's name in the format  and * reformats it to the form  {} means may or may not be present * * * * * * Preconditions: the string is not empty there is exactly one ',' (comma) and it comes at the end of the Last name there is 1 space after the comma there may or may not be a middle initial after the first name If there is a middle initial, it will be separated from the first name by a single space The middle initial will be followed by a '.' and 0 or more spaces. * * * * * Here are some examples (" "Alex P Keaton"  * * public static String stringReformat( String name) {