Question: Just for question (c), Rewrite the code for mystery using a foldr 5. A programmer writes the following code but fails to provide types: data

Just for question (c), Rewrite the code for mystery using a foldr
5. A programmer writes the following code but fails to provide types: data SF a = ss a | FF deriving (Show, Eq) myhead 1 FF myhead (a:as) SS a mytail 0 [] mytail (:xs) XS [] myzip [] myzip 0 = [] myzip (a:as) (b:bs) (a,b): (myzip as bs) mystery xs myhead [x|(x, y)
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