Question: Regarding following Haskell code 5. A programmer writes the following code but fails to provide types: data SF a = ss a FF deriving (Show,
Regarding following Haskell code

5. A programmer writes the following code but fails to provide types: data SF a = ss a FF deriving (Show, Eq) myhead FF myhead (a:as) SS a mytail (1 [] mytail (:xs) XS myzip [ 0 1 myzip [] = [] myzip (a:as) (b:bs) (a,b): (myzip as bs) mystery xs myhead (x(x,y)
Step by Step Solution
There are 3 Steps involved in it
To determine the types for myhead mytail myzip and mystery lets break down each function 1 myhead D... View full answer
Get step-by-step solutions from verified subject matter experts
