JUST PART C$!!!!!!!!$

A circular area with a radius of $7\mathrm{.}40$ cm lies in the $x-y$ plane.

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Part A

What is the magnitude of the magnetic flux through this circle due to a uniform magnetic field $B=0\mathrm{.}231T$ that points in the $+z$ direction?

Express your answer in webers.

Previous Answers

Correct Important: If you use this answer in later parts, use the full unrounded value in your calculations.

Set Up: ${}_B=$BAcos$.$ The normal to the loop is in the $z$ direction. The loop has area

$A=r^2=(7\mathrm{.}40{10}^{-2}(m){)}^2=1\mathrm{.}72{10}^{-2}{m}^2$

Solve: $=0.{}_B=BA=(0\mathrm{.}231T)(1\mathrm{.}72{10}^{-2}{m}^2)=3\mathrm{.}97{10}^{-3}Wb$

Part B

What is the magnitude of the magnetic flux through this circle due to a uniform magnetic field $B=0\mathrm{.}231T$ that points at an angle of $53\mathrm{.}2$ from the $+z$ direction?

Express your answer in webers.

${}_B=2\mathrm{.}38{10}^{-3}Wb$

Previous Answers

Correct

$=53\mathrm{.}2*{}_B=$BAcos$53\mathrm{.}2=(3\mathrm{.}97{10}^{-3}(Wb))cos53\mathrm{.}2=2\mathrm{.}38{10}^{-3}Wb$

Part C

What is the magnitude of the magnetic flux through this circle due to a uniform magnetic field $B=0\mathrm{.}231T$ that points in the $+y$ direction?

Express your answer in webers.