Exercise: Develop an IPR curve for the well described below. The drainage radius is 1490 ft...

 

Transcribed Image Text:

Exercise: Develop an IPR curve for the well described below. The drainage radius is 1490 ft and the skin effect is zero. k = 13 md (from cores) h = 115 ft Pi = 4350 psi Pb = 4350 psi Co Cw = 3 x 10-6 Cf 3.1 x 10-6 Psi-1 Psi-1 C₁ = 1.25 x 10-5 psi-¹ Ho F = 1.2 x 10-5 = 1.7 cp Yo = 32° API Yg = 0.71 T = 180°F Tpc = 395°R Ppc = 667 psi Sw= 0.3 = 0.21 rw = 0.406 ft Bo (res BBI/STB) B (res ft³/SCF) Rg (SCF/STB) 1.6 1.5 1.4 1.3 1.2 1.1 1.0 0 0.020 0.016 0.012 0.008 0.004 0.000 1000.0 800.0 600.0 400.0 200.0 0.0 0 0 1000 1000 1000 2000 3000 Pressure (psi) 2000 3000 Pressure (psi) 2000 3000 Pressure (psi) 4000 4000 4000 5000 5000 5000 9⁰ 90 == kohğ[1 – 0.2(Pwƒ/p) – 0.8(Pwƒ/P)²] 254.2B..[In(0.472re/rw) + s] When p = 4350 psi, 90 = 1411. 1-0.2 - 0.8 1411 [1 P Flowing Bottomhole Pressure. p (psi) 5000 4000 3000 2000 1000 0 0 500 -0.8(P) ] 1000 Flowrate, q, (STB/d) The IPR curve is no longer straight line! p=4350 1500 Exercise: Develop an IPR curve for the well described below. The drainage radius is 1490 ft and the skin effect is zero. k = 13 md (from cores) h = 115 ft Pi = 4350 psi Pb = 4350 psi Co Cw = 3 x 10-6 Cf 3.1 x 10-6 Psi-1 Psi-1 C₁ = 1.25 x 10-5 psi-¹ Ho F = 1.2 x 10-5 = 1.7 cp Yo = 32° API Yg = 0.71 T = 180°F Tpc = 395°R Ppc = 667 psi Sw= 0.3 = 0.21 rw = 0.406 ft Bo (res BBI/STB) B (res ft³/SCF) Rg (SCF/STB) 1.6 1.5 1.4 1.3 1.2 1.1 1.0 0 0.020 0.016 0.012 0.008 0.004 0.000 1000.0 800.0 600.0 400.0 200.0 0.0 0 0 1000 1000 1000 2000 3000 Pressure (psi) 2000 3000 Pressure (psi) 2000 3000 Pressure (psi) 4000 4000 4000 5000 5000 5000 9⁰ 90 == kohğ[1 – 0.2(Pwƒ/p) – 0.8(Pwƒ/P)²] 254.2B..[In(0.472re/rw) + s] When p = 4350 psi, 90 = 1411. 1-0.2 - 0.8 1411 [1 P Flowing Bottomhole Pressure. p (psi) 5000 4000 3000 2000 1000 0 0 500 -0.8(P) ] 1000 Flowrate, q, (STB/d) The IPR curve is no longer straight line! p=4350 1500

Answer rating: 100% (QA)

The detailed expla... View the full answer