Kim has $24 per week in her entertainment budget. She splits her time between going to...

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Kim has $24 per week in her entertainment budget. She splits her time between going to the movies and yoga classes. Each movie costs $8 while each yoga class costs $3. The total utility from each of these activities is set out in the table below. What is Kim's total utility maximizing point? Movies Total Utility Yoga Classes Total Utility 40 30 12 75 55 3 105 76 4 130 92 5 160 5 106 6 114 116 117 O O movies, 8 yoga classes O 1 movie, 5 yoga classes O 2 movies, 2 yoga classes O 3 movies, O yoga classes QUESTION 38 Aleah is an electrical engineer. Her wage increased from $30 per hour to $40 per hour. She can work up to 50 hours each week. The table below shows her utility from different levels of leisure and income. If Aleah decreased her hours of work from 30 to 20 hours per week before her raise, the marginal utility loss from having less income is: Hours of Leisure Total Utility from Leisure Income Total Utility from Income 10 29 300 42 20 54 400 74 30 73 600 96 40 86 800 113 50 92 900 119 1200 122 1500 124 1600 126 2000 127 O 23 O 56 O 19 O 100 The amounts (in oz) in cans of soda are given below. The cans are labeled to indicate that the contents are 12 oz of soda. Use a 0.05 significance level to test the claim that the cans are filed so that the median amount is 12 oz. If the median is not 12 az, are consumers being cheated? m Click the icon to view the data table Amounts (in oz) in cans of a certain Click here to view page.one of the standard normal distribution table Click here to view.page two of the standard normal distribution table soda First define the null and altemative hypotheses. Volume Regular Soda 12.0 11.8 123 122 122 11.8 122 12.1 12.2 12.1 12.0 12.2 11.8 12.3 11.8 12.1 12.3 11.8 12.0 12.3 11.8 12.1 12.2 12.3 11.9 12.0 12.2 11.8 12.4 12.1 12.2 Calculate the Wilconon test statistic T-O 123 122 12.2 12.2 12.1 Since the sample sizen is greater than 30, convert T to a z test statistic. (Round to two decimal places as needed.) Determine the critical value(s). Print Done The critcal value(s) is/are (Round to two decimal places as needed. Use a comma to separate answers as needed) Choose the comect answer below. OA Fail to reject He There is insufficient evidence to warrant rejection of the claim that the median amount of soda is 12.0 oz. B. Fail to reject Ho There is sufficient evidence to warrant rejection of the claim that the medan amount of soda is 12.0 oz. C. Reject H. There is insufficient evidence to warrant rejection of the claim that the median amount of soda is 12.0 oz. OD. Reject Hy. There is sufficient evidence to warrant rejection of the claim that the median amount of soda is 12.0 oz. Are consumers being cheated? A Since the median of the sample is 12.15, there is no reason to suspect that consumers are being cheated. B. Since the median of the sample is 12.15, there is a reason to suspect that consumers are being cheated. C. Since the null hypothesis was not rejected, there is no reason to suspect that consumers are being cheated D. The sample mean is 12.0 cz. Kim has $24 per week in her entertainment budget. She splits her time between going to the movies and yoga classes. Each movie costs $8 while each yoga class costs $3. The total utility from each of these activities is set out in the table below. What is Kim's total utility maximizing point? Movies Total Utility Yoga Classes Total Utility 40 30 12 75 55 3 105 76 4 130 92 5 160 5 106 6 114 116 117 O O movies, 8 yoga classes O 1 movie, 5 yoga classes O 2 movies, 2 yoga classes O 3 movies, O yoga classes QUESTION 38 Aleah is an electrical engineer. Her wage increased from $30 per hour to $40 per hour. She can work up to 50 hours each week. The table below shows her utility from different levels of leisure and income. If Aleah decreased her hours of work from 30 to 20 hours per week before her raise, the marginal utility loss from having less income is: Hours of Leisure Total Utility from Leisure Income Total Utility from Income 10 29 300 42 20 54 400 74 30 73 600 96 40 86 800 113 50 92 900 119 1200 122 1500 124 1600 126 2000 127 O 23 O 56 O 19 O 100 The amounts (in oz) in cans of soda are given below. The cans are labeled to indicate that the contents are 12 oz of soda. Use a 0.05 significance level to test the claim that the cans are filed so that the median amount is 12 oz. If the median is not 12 az, are consumers being cheated? m Click the icon to view the data table Amounts (in oz) in cans of a certain Click here to view page.one of the standard normal distribution table Click here to view.page two of the standard normal distribution table soda First define the null and altemative hypotheses. Volume Regular Soda 12.0 11.8 123 122 122 11.8 122 12.1 12.2 12.1 12.0 12.2 11.8 12.3 11.8 12.1 12.3 11.8 12.0 12.3 11.8 12.1 12.2 12.3 11.9 12.0 12.2 11.8 12.4 12.1 12.2 Calculate the Wilconon test statistic T-O 123 122 12.2 12.2 12.1 Since the sample sizen is greater than 30, convert T to a z test statistic. (Round to two decimal places as needed.) Determine the critical value(s). Print Done The critcal value(s) is/are (Round to two decimal places as needed. Use a comma to separate answers as needed) Choose the comect answer below. OA Fail to reject He There is insufficient evidence to warrant rejection of the claim that the median amount of soda is 12.0 oz. B. Fail to reject Ho There is sufficient evidence to warrant rejection of the claim that the medan amount of soda is 12.0 oz. C. Reject H. There is insufficient evidence to warrant rejection of the claim that the median amount of soda is 12.0 oz. OD. Reject Hy. There is sufficient evidence to warrant rejection of the claim that the median amount of soda is 12.0 oz. Are consumers being cheated? A Since the median of the sample is 12.15, there is no reason to suspect that consumers are being cheated. B. Since the median of the sample is 12.15, there is a reason to suspect that consumers are being cheated. C. Since the null hypothesis was not rejected, there is no reason to suspect that consumers are being cheated D. The sample mean is 12.0 cz.

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Ans Movies Total Utility MUx MuxPx Yoga Classes Total Utility Muy MuyPy 0 0 0 0 1 40 40 5 ... View the full answer