Knowing that the Room structure is defined as: 5truct Room \{ Distance length; Distance width; \}; In the above bedroom example, the length data member is initialed to {12,4.} ( 12 feet and 4.0 inches) and the width member is initialized to \{ 16,.0 ) (16 feet and 0.0 inches). The dot operator To access the individual data members of these structure objects, we use the dot operator. Given the above date object mlk_day, for example, we can use the pattern: object-name>. data-member-names to access the data members of this object and print them in the familiar Month/Day/Year format like this: We can also use the dot operator to set values for an object. For example, we can set the values of the day, month, and year members of the previously defined dob object by doing something like this. In[]:dob.day-27;dob.month-8;dob.year-2021; And for complex nested structures like Room where we have substructures (like Distance ), we can use multiple dot operators like this: In [ ]: cout "Bedroom measurements: " endl " length = bedroom. length. feet "" bedroom. length. inches " endl " width =" bedroom.width. feet " " bedroom . width.inches endl; CODING CHALLENGE 2 Use the next three code cells to define three structure variables, initialize them to the given values, and print their values. In [ ]: // ToDo: define a date variable named 'today' and imitialize it to today's values. I/ TODO: print the values of this variabte. In [ ]: // TOD0: define a time variable named 'noon' and initialize it to time 12+00:00. Use the I/ Time structure you created for the previous CODING CHALLENGE. I/ TOD0: print the values of this variable. In [ ]: // T000: define a distance variable named "height' and initialize it to 10 feet and 7.5 inches