$ln[A]=-kt+ln[A{]}_0$

Where:

$[A]=$ concentration $of$ reactant $A$

$\{\begin{array}{c}\text{:}[A{]}_0\end{array}=$ initial concentration $of$ reactant $A$

$k=$ rate constant

$t=$ time

In order to solve for the rate constant, $k,$ in two steps you must:

Step One

Add the same expression to each side of the equation to leave the term that includes the variable by itself on the right$-$hand side of the expression:

$($Be sure that the answer field changes from light yellow to dark yellow before releasing your answer.$)$

$$

$+ln[A]=$

$-kt+ln[A{]}_0$

Drag and drop your selection from the following list to complete the answer:

$\frac{1}{ln[A_0]}-ln[A_0]$

$ln[A_0]$

$-\frac{1}{ln[A_0]}$