Lab Intro To Micropocessor

This is lab working on CodeWarrior but you can do it on a paper

The maximum value of a byte is 255 (OxFF). Which means the maximum number of times we can make iterations is 255 which puts a limitation on us. What if we want to repeat a part of code more than 255 times? Let's say 700 times. Loop inside a loop approach In such a case we make use of a loop within loop. We already know about nested for loops in C and we are familiar how the nested loop can multiply the number of iterations. Use this approach in the following task. Write an assembly code to increment accumulator D 700 times. Initialize the register D with value 0 and in each iteration complement it (COM A complements register A). Create a variable 'i' to keep track of the outer loop, and another variable 'j' for the inner loop The total number of iterations of a nested loop equals to the product of the times each loop runs. i.e. If loopl runs 100 times and loop2 runs 2 times total number of iterations for the instruction lying inside loop2 would be 100*2=200. In the lab report draw a flowchart diagram for the code you write. The maximum value of a byte is 255 (OxFF). Which means the maximum number of times we can make iterations is 255 which puts a limitation on us. What if we want to repeat a part of code more than 255 times? Let's say 700 times. Loop inside a loop approach In such a case we make use of a loop within loop. We already know about nested for loops in C and we are familiar how the nested loop can multiply the number of iterations. Use this approach in the following task. Write an assembly code to increment accumulator D 700 times. Initialize the register D with value 0 and in each iteration complement it (COM A complements register A). Create a variable 'i' to keep track of the outer loop, and another variable 'j' for the inner loop The total number of iterations of a nested loop equals to the product of the times each loop runs. i.e. If loopl runs 100 times and loop2 runs 2 times total number of iterations for the instruction lying inside loop2 would be 100*2=200. In the lab report draw a flowchart diagram for the code you write