Question: Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the reaction Pb(NO 3 ) 2 (aq)+ 2NH 4 I(aq)

Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the reaction

Pb(NO3)2(aq)+ 2NH4I(aq) PbI2(s)+2NH4NO3(aq)

What volume of a 0.650 M NH4I solution is required to react with 819 mL of a 0.560 M Pb(NO3)2 solution?

How many moles of PbI2 are formed from this reaction?

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