Learning Goal:

Coulomb's law, electric fields, and the connection between the electric field and the electric force.

The connection between electric FIELD and Eelectric FORCE is: vec$(F)=$qvec$(E).$

This is a VECTOR equiation $-$ be careful with magnitude and directon.

The magnitude of the electric field by a SINGLE Point SOURCE Charge $Q$ is given by:

$E=k\frac{|Q|}{r^2},$

The directions of the electric field vectors created by a SINGLE Positive SOURCE Charge $($the RED arrows on the left side$),$ and by a SINGLE

Negative SOURCE Charge $($the BLUE arrows on the right side$)$ are shown

You will use a new approach to solve the previous problem in which three point electric charges are on a Tr

Make sure the angle setting in your calculator is "Degree". $sin30=0.$

Before putting anyt charge at Origin, the configuration is shown in left panel $($Figure $2)$

$q_1=280C,q_3=-4\mathrm{.}40C,1C={10}^{-6}C$ use $k=9\mathrm{.}00{10}^9\frac{N}{m^2{C}^2}$ for the Coulomb Constant.

$d_{13}=0\mathrm{.}240m,$ angle $=39,d_{12}=d_{23}=0\mathrm{.}1544m$

Part A $-$ Calculate the magnitude of the electric FIELD at the origin by charge q$1.$