Question: Learning Goal: Power and Work - KE Theorem FL A suitcase is being lifted upward by a string wrapped around a pully. The machine



Learning Goal: Power and Work - KE Theorem FL A suitcase is being lifted upward by a string wrapped around a pully. The machine that controls the pully and the string has a power of P = 1.7 hp. 1hp = 746 Watt. The suitcase' mass is m = 23.8 kg, The magnitude of the gravitational acceleration is 9.80 m/s. Part A - Convert the power to Watts. Keep 1 digit after the decimal point. Power = 1268.2 Watt Submit Previous Answers Correct Part B - How much work is done by the machine that controls the pully and the string in lifting the suitcase upward through a displacement of 10.0 m at a constant speed? Round to an integer. Unit is Joules. Work 2332. J Submit Previous Answers Correct > Part C - How much time does the machine (that controls the pully and the string) spend in lifting the suitcase upward through a displacement of 10.0 m ? Keep 2 digits after the decimal point.. Unit is Seconds. time 1.84 s Submit Previous Answers Part D - Convert 60 mph to m/s. 1 mile = 1609 m, 1 hour = 3600 s Keep 2 digits after the decimal point. Unit is m/s Case 2 speed f = 26.82 m/s Submit Previous Answers Correct > Part E-Calculate the work done by the engine force in achieving this speed increase. Note: this work can be calculated even though the engine force and/or displacement are not given explicitly. If you are not sure about how, open the "hints". Keep 0 digit after the decimal point. Unit is Joules. View Available Hint(s) ? Case 2 Work by engine force = 359.567 Submit Previous Answers Request Answer Incorrect; Try Again; One attempt remaining Part F - Case 2: What is the horsepower of the car's engine? The time of the speed increase is 6.8 s . Part F - Case 2: What is the horsepower of the car's engine? The time of the speed increase is 6.8 s. Keep 2 digits after the decimal point. Case 2 horsePower = Submit Request Answer ? hp no
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To solve Part E you need to calculate the work done using the kinetic energy theorem ... View full answer
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