Question: Learning Task 2: Solve It! 1. A 25.0 m metal rod moves at a speed Solution: of 5 m/s perpendicular to a magnetic 8 =

Learning Task 2: Solve It! 1. A 25.0 m metal rod moves at a speed Solution: of 5 m/s perpendicular to a magnetic 8 = Blv field of intensity 1.4 T. Find the resulting potential difference at the 8 = (1.4) (25) (5) ends of the rods. 8 = 175 V 2. A square loop with 5 cm sides is Solution: perpendicular to a uniform field 150 op = BA cose mT in intensity. If a third of this flux p = (150 x 10-3) (0.052) cos 0 remains every 0.010 s, what is the p = 375 HWb average emf induced? Acp E = -N- At (375 HWb) E = -(1) 0.010 &= -0.0125 V

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