Let

${\displaystyle \underset{0}{\overset{2}{}}}f(x)dx=6,{\displaystyle \underset{0}{\overset{3}{}}}f(x)dx=8,{\displaystyle \underset{0}{\overset{2}{}}}g(x)dx=-14,{\displaystyle \underset{2}{\overset{3}{}}}g(x)dx=3$

Use these values to evaluate the given definite integrals.

a$){\displaystyle \underset{0}{\overset{2}{}}}(f(x)+g(x))dx=$

b$){\displaystyle \underset{0}{\overset{3}{}}}(f(x)-g(x))dx=$

c$){\displaystyle \underset{2}{\overset{3}{}}}(3f(x)+2g(x))dx=$

d$)$ Find the value a such that ${\displaystyle \underset{0}{\overset{3}{}}}(af(x)+g(x))dx=0.$

$a=$

Note: You can earn partial credit on this problem.

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