Question: Let 2ux T.(x) = if 0 if O s r s 1/2 2u(1 T) if 1/2 < TSI Notice that when u = 1 we

if O s r s 1/2 2u(1 T) if 1/2 < TSI

Notice that when u = 1 we recover the Tent function (T@))

Let 2ux T.(x) = if 0

if O s r s 1/2 2u(1 T) if 1/2 < TSI Notice that when u = 1 we recover the Tent function (T@)) Show that 1/2 is an eventually fixed point of the function T

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